170=0.2x^2-92x+11

Solution for 170=0.2x^2-92x+11 equation:

170=0.2x^2-92x+11

We move all terms to the left:

170-(0.2x^2-92x+11)=0

We get rid of parentheses

-0.2x^2+92x-11+170=0

We add all the numbers together, and all the variables

-0.2x^2+92x+159=0

a = -0.2; b = 92; c = +159;
Δ = b2-4ac
Δ = 922-4·(-0.2)·159
Δ = 8591.2
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(92)-\sqrt{8591.2}}{2*-0.2}=\frac{-92-\sqrt{8591.2}}{-0.4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(92)+\sqrt{8591.2}}{2*-0.2}=\frac{-92+\sqrt{8591.2}}{-0.4}
$